shell scripting : seq prints a sequence of numbers
Filed Under (bash) by Amandine on 08-02-2010
I often need to execute a loop x times, and I’m just too lazy to write a i++ style algorithm… the command seq is made for me :)
Easy to use, just does what I need from it, here’s a extract from the man page :
NAME
seq - print a sequence of numbers
SYNOPSIS
seq [OPTION]... LAST
seq [OPTION]... FIRST LAST
seq [OPTION]... FIRST INCREMENT LAST
seq - print a sequence of numbers
SYNOPSIS
seq [OPTION]... LAST
seq [OPTION]... FIRST LAST
seq [OPTION]... FIRST INCREMENT LAST
So…
$ seq 10
1
2
3
4
5
6
7
8
9
10
1
2
3
4
5
6
7
8
9
10
$ seq 5 10
5
6
7
8
9
10
5
6
7
8
9
10
$ seq 10 2 20
10
12
14
16
18
20
10
12
14
16
18
20
$ for i in `seq 5`; do echo 'hello!'; done;
hello!
hello!
hello!
hello!
hello!
hello!
hello!
hello!
hello!
hello!
Great ! :p
